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(C) The vector $(\overrightarrow{A} - \overrightarrow{B})$ lies in the plane formed by vectors $\overrightarrow{A}$ and $\overrightarrow{B}$.By the de

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$90$

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(C) The vector $(\overrightarrow{A} - \overrightarrow{B})$ lies in the plane formed by vectors $\overrightarrow{A}$ and $\overrightarrow{B}$.By the definition of the cross product,the vector $(\overrightarrow{A} 	imes \overrightarrow{B})$ is perpendicular to the plane containing both $\overrightarrow{A}$ and $\overrightarrow{B}$.Since $(\overrightarrow{A} - \overrightarrow{B})$ lies in the plane of $\overrightarrow{A}$ and $\overrightarrow{B}$,the vector $(\overrightarrow{A} 	imes \overrightarrow{B})$ must be perpendicular to $(\overrightarrow{A} - \overrightarrow{B})$.Therefore,the angle between $(\overrightarrow{A} - \overrightarrow{B})$ and $(\overrightarrow{A} 	imes \overrightarrow{B})$ is $90^{\circ}$.

The angle between $(\overrightarrow{A} - \overrightarrow{B})$ and $(\overrightarrow{A} \times \overrightarrow{B})$ is $(\overrightarrow{A} \neq \overrightarrow{B})$. (in $^{\circ}$)

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